Question Solve $\sin(3x)=\cos(2x)$ for $0≤x≤2\pi$. My knowledge on the subject; I know the general identities, compound angle formulas and double angle formulas so I can only apply those. Answer(1 of 3): Sin x/cos^2x=2cos x. tan x=2cos^2 x tan x=2/sec^2 x=2/(1+tan^2 x) tan x+tan^3x-2=0 (tanx-1)+(tan^3 x-1)=0 (tanx -1)+(tan x-1)(tan^2 x+tan x+1)=0 (tan cara memperbaiki charger laptop asus tidak mengisi. Trigonometry Examples Solve for x 2sinx=cosx Step 1Divide each term in the equation by .Step 5Cancel the common factor of .Step the common 6Divide each term in by and the common factor of .Step the common 7Take the inverse tangent of both sides of the equation to extract from inside the 9The tangent function is positive in the first and third quadrants. To find the second solution, add the reference angle from to find the solution in the fourth 10Step 11Step period of the function can be calculated using .Step with in the formula for absolute value is the distance between a number and zero. The distance between and is .Step 12The period of the function is so values will repeat every radians in both directions., for any integer Step 13Consolidate and to ., for any integer

cos x sin x cos 2x